\({\log _a}a = 1\) (since \({a^1} = a\)) so \({\log _7}7 = 1\) \({\log _a}1 = 0\) (since \({a^0} = 1\)) so \({\log _{20}}1 = 0\) \({\log _a}p + {\log _a}q = {\log _a ...
Solve the equation \(5(2c - 3) = 19\). The equation contains a set of brackets. The easiest way to solve equations with brackets is to expand the brackets. \(\text{Area of a rectangle} = \text{base} ...
A mathematician has built an algebraic solution to an equation that was once believed impossible to solve. The equations are fundamental to maths as well as science, where they have broad applications ...
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